Problem:
Please find the problem here.
Solution:
The problem size is just too small - consider the set of all pairs or 3 digits numbers = $ (999-100+1)^2 = 810000 $, any computer is going to find the answer very quickly. Here is the code:
At this point - don't you think Project Euler problem is really simple? All just brute force, isn't it. NO! Problems are getting harder and harder, you will see them soon.
Answer: 906609
Please find the problem here.
Solution:
The problem size is just too small - consider the set of all pairs or 3 digits numbers = $ (999-100+1)^2 = 810000 $, any computer is going to find the answer very quickly. Here is the code:
namespace Euler { using System; using System.Collections.Generic; using System.Linq; internal static partial class Program { public static void Problem004() { int max = 0; for (int i = 999; i >= 100; i--) { for (int j = 999; j >= 100; j--) { int candidate = i * j; if (candidate == Reverse(candidate)) { if (candidate > max) { max = candidate; } } } } Console.WriteLine(max); } private static int Reverse(int i) { int j = 0; while (i > 0) { j = j * 10 + i % 10; i = i / 10; } return j; } } }
At this point - don't you think Project Euler problem is really simple? All just brute force, isn't it. NO! Problems are getting harder and harder, you will see them soon.
Answer: 906609
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